Library's Namespace

Namespace Export Example

In order to use a library namespace, a library should be registered first via Unigine::Interpreter::addExternLibrary().
After that, you can use a library namespace to register your variables and functions.

Source code (C++)

#include <UnigineEngine.h>
#include <UnigineInterpreter.h>
#include <UnigineInterface.h>

#include "AppSystemLogic.h"
#include "AppWorldLogic.h"
#include "AppEditorLogic.h"


using namespace Unigine;

// A variable within a namespace for export.
namespace Foo {
	int i = 25;
}

#ifdef _WIN32
	int wmain(int argc,wchar_t *argv[]) {
#else
	int main(int argc,char *argv[]) {
#endif

	// Register a library in order to use a library namespace.
	Interpreter::addExternLibrary("Foo");

	// Export a variable with a library prefix.
	Interpreter::addExternVariable("Foo.integer",MakeExternVariable(&Foo::i));

	AppSystemLogic system_logic;
	AppWorldLogic world_logic;
	AppEditorLogic editor_logic;
	
	Unigine::EnginePtr engine(UNIGINE_VERSION,argc,argv);

	// Enter main loop.
	engine->main(&system_logic,&world_logic,&editor_logic);

	return 0;
}

Access from Scripts

You can simply call the registered variables, functions, classes from Unigine scripts using the registered name. (If Foo library is not registered, the first dot in an object or function name is treated as an operator of class member access, which is wrong in our case).

In the init() function of the world script .cpp file add the following:

Source code (UnigineScript)

// my_world.cpp

int init() {
	/* ... code ... */

	log.message("Foo.i is %d\n",Foo.integer);
	engine.console.setActivity(1);

	/* ... code ... */

}

Output

The following console message will be printed:

Output

Foo.i is 25

Last update: 03.07.2017

Помогите сделать статью лучше

Была ли эта статья полезной?

Сообщить о проблеме в этой статье

(или выберите слово/фразу и нажмите Ctrl+Enter

Library's Namespace

In This Article:

Namespace Export Example

Access from Scripts

Output